Hi,
I solved a similar problem with Marcus' example here. But I have another advanced question:
I have the following site structure:
Maybe someone can give me some help, an idea or an example.
Thanks,
Thorsten
I solved a similar problem with Marcus' example here. But I have another advanced question:
I have the following site structure:
- Home
- Big Houses
-
Destinations
-
Sweden
- House A
- House B
- House C
-
Denmark
- House A
- House B
- House C
-
Italy
- House A
- House B
-
House C
-
Sweden
<xsl:for-each select="/in:inputs/in:result[@name='SitemapXml']/Page">
<xsl:variable name="laenderinfos" select="/in:inputs/in:result[@name='GetLaenderinfosXml']/Laenderinfos[@PageId=current()/@Id]" />
<!-- 1/3 Column -->
<div class="one-third column portfolio-item scenery">
<div class="picture"><a href="~/Page({$laenderinfos/@PageId})"><img src="~/media({($laenderinfos/@Bild.KeyPath)})?mw=500" alt=""/><div class="image-overlay-link"></div></a></div>
<div class="item-description alt">
<h3><a href="~/Page({$laenderinfos/@PageId})"><xsl:value-of select="$laenderinfos/@PageId.MenuTitle" /></a></h3>
<!--<p><xsl:value-of select="$laenderinfos/@Beschreibung" /></p>-->
</div>
</div>
</xsl:for-each>
On the country pages (Sweden, Denmark, Italy,...) I have the following xslt-function to display the houses (House A, House B, House C,...) with their MetaData (Image, Description, ...):<xsl:for-each select="/in:inputs/in:result[@name='SitemapXml']/Page">
<xsl:variable name="reiseinfos" select="/in:inputs/in:result[@name='GetReiseinfosXml']/Reiseinfos[@PageId=current()/@Id]" />
<!-- 1/4 Column -->
<div class="four columns portfolio-item">
<div class="picture"><a href="~/Page({$reiseinfos/@PageId})"><img src="~/media({($reiseinfos/@Bild.KeyPath)})?w=220&h=165" alt=""/><div class="image-overlay-link"></div></a></div>
<div class="item-description alt">
<h5><a href="~/Page({$reiseinfos/@PageId})"><xsl:value-of select="$reiseinfos/@PageId.MenuTitle" /></a></h5>
<p><xsl:value-of select="$reiseinfos/@Beschreibung" /></p>
</div>
</div>
</xsl:for-each>
Now I want to show a subset from all houses of all countries with a special 'House Type' defined in their MetaData (e.g. "Big Houses") on a separate page 'Big Houses' - but ordered like in the tree (Show me all "Big Houses" on one page)- House A from Sweden
- House C from Sweden
- House B from Denmark
- House C from Denmark
-
House C from Italy
Maybe someone can give me some help, an idea or an example.
Thanks,
Thorsten